引用第656楼iongwaichun于2008-12-02 21:45发表的 :
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1114523221
! ^. t# ~# m2 g) R9 ?重做一次後,Here is my solution
, l& z0 M- Z4 P6 ]8 ? d6 Z. ? v# b1 U5 H) d! R
' _( n9 [0 j1 G- x* Z
P8:9 I6 y8 X. Q8 p5 q3 \$ M" g) E& ~4 v
Here is my deduction:5 J c8 }8 V/ Y
From the left 3 digit, we can deduct the following:( w' p4 z! B2 z7 x% ~
112( d9 H0 R$ @0 t
1118 D8 t0 i7 V: k$ t+ I
112/ u' `: y" p. D& j) I. W
111" y y' z0 A! a9 i+ ^: y4 R& W
1136 w/ z/ n7 E% U* a
So, the final line = 111
8 w! b+ ]' I" v# U! A1 L$ T
$ f+ C0 f; s; X, A2 ^/ x2 u4 J. _* _- n2 i
From the right 3 digit, we can deduct the following(S):( p$ k* a1 ^0 {. M
1213 S' B4 w& v! H6 @! e& h2 m; _) n) C
221
1 U+ w- r- k1 i6 H+ |; G231
6 i E. _8 @* _: {$ P221+ I& D# L W4 n
331
. n0 w9 ~7 M) ^
# M' X7 E" k6 B$ rSo, the final Line = 221- `/ W7 |7 Q9 C* d' x
4 Y' _- d% H; t8 O0 b- ^/ C# \
In the uppesmost line, the middle letters had been use twice, they are 1 and 2
( k7 h# Z" R: k& B4 D1 A B+ }From the remaining numbers, there are 32 on the second last line provided,. B, q" B& \0 d/ \" E" y
and 21 on the last line' O) r8 ^( o; M; `
4 N- k" N! `3 ?0 d0 N! I, w: x2 t# r
We now had the sequence:2 f! g, N' }1 ?! s7 @& ~
12
# T G3 {# r' O/ @$ W32& \# o+ Z6 h9 u( d! }- q+ s
21 Y4 J4 q- V, C: Y
6 O$ l* s4 c7 r6 s$ _
So, the last line's middle numbers is 23 (exchange the two numbers)
g1 t3 ^9 \8 ?4 f3 T, g" C; `, P6 s7 V- N& p# B) S) K* `) v
Now we have the following numbers:
9 T! A3 t3 w( ~( B9 _; A5 V111x23y221
& z* I0 u! d4 w9 QCulculate the total of every line, then we can conclude the following
. [; c* W6 \! R# UDifference between line 1 and line 2=3, P k7 B5 C" z. g+ ]) X; E
Difference between line 2 and line 3=2
3 U6 \6 D1 v* P0 RDifference between line 3 and line 4=3/ N+ @$ z" p* W$ @
Difference between line 4 and line 5=2$ _/ c. Q! n, N5 E( M$ q3 r, {
So, Difference between line 5 and line 6=3
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But now, the total of our deduction=13
. V3 j: b6 C; ALine 5's total=15
3 J/ j7 I: L# ?1 hwhich means X+Y=(15+3)-135 d8 R W. e2 X2 C- G* g! W
=18-13
; r3 ]. X) @( o8 A2 _ =5
# J2 D. ?/ t+ N8 l4 }So, If x=2, y=3! L' ?2 U9 c9 e! B1 W8 x
x=3, y=27 g% N5 Q$ O. Q& b: p9 w2 b
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0 e- s& J. y' ^5 A/ s* b0 ]1 O5 t3 g8 iAns=1112233221
7 w2 ~% v5 X! _8 _4 L; T+ for
; e% Z$ r( m5 B1 ?Ans=1113232221 |